Keep in mind you only have 15 seconds to complete the challenge!!

In my case it was copy the text

-paste the text
-run my program
-copy the answer from my program
-paste it into the answer box
-and hit submit

timelimit is 15seconds once you open the page til you hit submit and the request is processed!

Work fast!

i do exactly the same less than 15 seconds.
have you take a look at my result above? how is it?

You are doing it wrong, your output should be like this:
(...)also almost said
You don’t have any “,” in it.

@heavenlyMe - sorry mate, I just needed to check. It took me about 20 attempts cause I was too slow. Anyway No disrespect intended!!

@ColdIV, is what i need to do is get rid all “,”?
@draethel, no problem mate :) i appreciate it anyway

Yes, you don’t need them in there, just the words and the spaces.

@ColdIV, thank you and finally solved the level :)

No problem and congratulation :)

Thank You ColdIV …This made me confused >>Put all these values in a csv e.g. 61,72,71 and (d: Get this characters original ascii value ) …Beside it was set of words and separated by spaces … How did you figure out it was words ?

@wence, you can try generate some random ascii chara and try to encrypt these chara with provided encryption algorithm. After you understand how it works, then try to decrypt it. I think the encrypted words was not intentionally made.

For those of you who are still copying, decoding and pasting answers from the page, here is a nifty add-on for chrome: Tampermonkey.
Simply install it and add a new script, much easier and quicker!
Hope this help you guys. For reference, I found this in a post in a previous level’s discussion!
Cheers

Hi,

I have reverse engineered the algo according to the instructions and i am inputting the result into the answer field (all using javascript/tampermonkey). the results are clear words and it should be ok. However it still says incorrect answer when I submit. Can I PM anyone with my javascript code and get a hint as to what’s missing/wrong?

Thanks!

I don’t know english very well, so maybe asomeone may help me.

Please correct my algorithm

Example:

the words are:

33,34,35,…

1. Re-number all visible ascii characters, so ! will now be
   1 instead of 33 and “ will be 2 instead of 34 and so on

I’ve add 32 for all:

65,66,67,…

1. Get each letter of your string and do the following:
   a: Get its new ascii code value

A,B,C

     b: Take this value, and subtract it from the total  
        number of visible ASCII characters  

total number of visible ASCII charavters: A B C … -> length=150

150-A -> 150-65 = 85;

     c: Get the character at this position  
     d: Get this characters original ascii value  

85 -> U
86 ->V

output: U, V, X, …

Tks.

I am still trying to figure out this level but thanks @bolofecal for your post.

It means number of visible ascii chars in the ascii table. Not in your string. This is a constant which remains throughout different instances of the challenge.

In wikipedia:

ASCII includes definitions for 128 characters: 33 are non-printing control characters (many now obsolete) that affect how text and space are processed and 95 printable characters, including the space (which is considered an invisible graphic).

So the number of visible ASCII characters is 95?

If you ever wonder which number is the right one to solve this level, how about trying all of them? It should be shorter than 5 minutes.

32   =   0   Space  
33   =   1   !  
34   =   2   "  
35   =   3   #  
36   =   4   $  
37   =   5   %  
38   =   6   &  
39   =   7     
40   =   8   (  
41   =   9   )  
42   =   10  *  
43   =   11  +  
44   =   12  ,  
45   =   13  -  
46   =   14  .  
47   =   15  /  
48   =   16  0  
49   =   17  1  
50   =   18  2  
51   =   19  3  
52   =   20  4  
53   =   21  5  
54   =   22  6  
55   =   23  7  
56   =   24  8  
57   =   25  9  
58   =   26  :  
59   =   27  ;  
60   =   28  <  
61   =   29  =  
62   =   30  >  
63   =   31  ?  
64   =   32  @  
65   =   33  A  
66   =   34  B  
67   =   35  C  
68   =   36  D  
69   =   37  E  
70   =   38  F  
71   =   39  G  
72   =   40  H  
73   =   41  I  
74   =   42  J  
75   =   43  K  
76   =   44  L  
77   =   45  M  
78   =   46  N  
79   =   47  O  
80   =   48  P  
81   =   49  Q  
82   =   50  R  
83   =   51  S  
84   =   52  T  
85   =   53  U  
86   =   54  V  
87   =   55  W  
88   =   56  X  
89   =   57  Y  
90   =   58  Z  
91   =   59  [  
92   =   60  \  
93   =   61  ]  
94   =   62  ^  
95   =   63  _  
96   =   64  `  
97   =   65  a  
98   =   66  b  
99   =   67  c  
100  =   68  d  
101  =   69  e  
102  =   70  f  
103  =   71  g  
104  =   72  h  
105  =   73  i  
106  =   74  j  
107  =   75  k  
108  =   76  l  
109  =   77  m  
110  =   78  n  
111  =   79  o  
112  =   80  p  
113  =   81  q  
114  =   82  r  
115  =   83  s  
116  =   84  t  
117  =   85  u  
118  =   86  v  
119  =   87  w  
120  =   88  x  
121  =   89  y  
122  =   90  z  
123  =   91  {  
124  =   92  |  
125  =   93  }  
126  =   94  ~  
127  =   95  DEL  

Based on the above table is my below analysis correct or I am completely wrong about it.

54,53,49, ,55,47,42, ,57,40,57,44,37, ,61,49,47,48,55, ,47,41,44, ,61,48,58, ,39,54,47, ,59,61,48,48,47,42, ,43,53,48,59,57, ,53,42,43, ,54,53,43, ,50,53,51,57, ,61,60,47,41,42

Get its new ascii code value == 54 = 22 = Value is 6
Take this value, and subtract it from the total number of visible ASCII characters == 95 - 6 = 89
Get the character at this position == y //Value is as per the new number assigned to it
Get this characters original ascii value == 121

So the answer at the end would all be all numbers correct. I mean in the .txt file it shows it should be in csv format like 61,72,71 but I just want to confirm.

I’ve used javascript to complete this mission. If someone need help maybe I can help, contact me, or if someone used another method contact me me too, I like learn about differents methods.

Almost given solution here bolofecal, could you edit your post =)
The principal difficulty here is the crypt method …

Keep getting incorrect with message already decrypted.
Here is the number

42,54,61,48, ,49,61,37, ,60,41,42, ,39,54,57,44,57, ,42,47,47, ,56,44,47,49, ,59,47,41,50,58, ,43,47,49,57, ,39,57,44,57, ,39,54,37, ,42,54,57,37, ,61,49,47,48,55, ,61,56,42,57,44, ,61,59,44,47,43,43
[/spoiler]
Here is msg
[spoiler]
THAN MAY BUT WHERE TOO FROM COULD SOME WERE WHY THEY AMONG AFTER ACROSS

It’s kind of confusing now, so can anyone tell me final results would be original msg ?
——- Updated ——-

Manage to solve it with output from thread’s owner. So the given code from the textarea was original acsii . I thought it was already encrypted.